Two objects with mass are placed 20 m away from one another and exert 1.2 x 10^{-30} N attractive force due to the gravity between them. What will the attractive force between the two objects be if the distance between them is reduced so the objects are now 10m apart?

Proportionality PBL

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What is the factor difference between the final and initial masses in the problem?

Question for Reference: Two objects with mass are placed 20 m away from one another and exert 1.2 x 10^{-30} N attractive force due to the gravity between them. What will the attractive force between the two objects be if the mass of one of the objects is doubled?

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Hint

Remember to find the factor difference take the final value and place it over the initial value. In this particular case, no final and initial values are given but the factor difference between them is already given to us by the word doubled. This means that the factor difference will be equal to 2.

Question 2 of 3

2. Question

Which of the following correctly displays the proportionality expression for mass in this question?

Question for Reference: Two objects with mass are placed 20 m away from one another and exert 1.2 x 10^{-30} N attractive force due to the gravity between them. What will the attractive force between the two objects be if the mass of one of the objects is doubled?

Correct

Incorrect

Hint

Here we need to recall the gravity equation which is

\[ F_g =\frac{Gm_1m_2}{r^2}

\]

then we will set everything except for one of the masses equal since only one mass changes in the question stem. This yields the following

\[F_g \propto m\]

Thus the correct answer is A.

Question 3 of 3

3. Question

By what factor will the new force differ in this question and what will the value of the force be?

Question for Reference: Two objects with mass are placed 20 m away from one another and exert 1.2 x 10^{-30} N attractive force due to the gravity between them. What will the attractive force between the two objects be if the mass of one of the objects is doubled?

Correct

Incorrect

Hint

When we plug our factor difference into our proportionality expression it is unchanged. Therefore the force will increase by a factor of two thus D is correct since 2.4 x 10^{-30 }is equal to 2 multiplied by the original force 1.2 x 10^{-30}.

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